Greenbush is a town in Sheboygan County, Wisconsin, United States. The population was 2,773 at the 2000 census. It is included in the Sheboygan, Wisconsin Metropolitan Statistical Area. The census-designated place of Greenbush is located in the town. The unincorporated community of German Corners is afterward located in the town.

According to the United States Census Bureau, the town has a total Place of 47.4 square miles (122.8 km), of which, 47.2 square miles (122.1 km²) of it is estate and 0.3 square miles (0.7 km) of it (0.55%) is water.

As of the census of 2000, there were 2,773 people, 526 households, and 433 families residing in the town. The population density was 58.8 people per square mile (22.7/km²). There were 551 housing units at an average density of 11.7 per square mile (4.5/km). The racial makeup of the town was 74.29% White, 23.15% African American, 1.73% Native American, 0.18% Asian, 0.04% Pacific Islander, 0.29% from other races, and 0.32% from two or more races. Hispanic or Latino of any race were 3.97% of the population.

There were 526 households, out of which 40.3% had children under the age of 18 living considering them, 75.9% were married couples lively together, 4.2% had a female householder taking into consideration no husband present, and 17.5% were non-families. 12.5% of all households were made in the works of individuals, and 4.9% had someone lively alone who was 65 years of age or older. The average household size was 2.91 and the average family size was 3.23.